Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 2 - Section 2.1 - Linear Equations in One Variable - Exercise Set: 8

Answer

$y = 7$

Work Step by Step

$5y - 3 = 11 + 3y$ $5y - 3 - 3y = 11 + 3y - 3y$ $5y - 3y - 3 = 11$ $2y - 3 = 11$ $2y - 3 + 3 = 11 + 3$ $2y = 14$ $(2y)\div2 = 14\div2$ $y = 7$ Check: $5(7) - 3 = 11 + 3(7)$ $35 - 3 = 11 + 21$ $32 = 32$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.