## Intermediate Algebra (6th Edition)

a=$\frac{4}{5}$
Original Equation $\frac{1}{4}$(a+2)=$\frac{1}{6}$(5-a) Multiply both sides by 12 3(a+2)=2(5-a) Distribute 3a+6=10-2a Add 2a and subtract 6 from both sides 5a=4 Divide both sides by 5 a=$\frac{4}{5}$