## Intermediate Algebra (6th Edition)

b=$\frac{1}{8}$
Original equation $\frac{3}{8}$+$\frac{b}{3}$=$\frac{5}{12}$ Multiply through by 24 to get rid of denominators 9+8b=10 Subtract 9 from both sides 8b=1 Divide both sides by 8 b=$\frac{1}{8}$