Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 2 - Section 2.1 - Linear Equations in One Variable - Exercise Set: 43

Answer

b=$\frac{1}{8}$

Work Step by Step

Original equation $\frac{3}{8}$+$\frac{b}{3}$=$\frac{5}{12}$ Multiply through by 24 to get rid of denominators 9+8b=10 Subtract 9 from both sides 8b=1 Divide both sides by 8 b=$\frac{1}{8}$
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