## Intermediate Algebra (6th Edition)

$x=\frac{40}{3}$
We are given that $\frac{3x-1}{9}+x=\frac{3x+1}{3}+4$. First, we can multiply each term by 9. Since this is the least common denominator of each term, this will eliminate all fractions from the equation. $\frac{3x-1}{9}\times9+x\times9=\frac{3x+1}{3}\times9+4\times9$ $3x-1+9x=3\times(3x+1)+36$ Use the distributive property to simplify the right side. $3x-1+9x=9x+3+36$ Group like terms on both sides. $12x-1=9x+39$ Add 1 to both sides. $12x=9x+40$ Subtract 9x from both sides. $3x=40$ Divide both sides by 3. $x=\frac{40}{3}$