Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 2 - Section 2.1 - Linear Equations in One Variable - Exercise Set: 28

Answer

$h=1$

Work Step by Step

We are given that $\frac{2+h}{9}+\frac{h-1}{3}=\frac{1}{3}$. First, we can multiply each term by 9. Since this is the least common denominator of each term, this will eliminate all fractions from the equation. $\frac{2+h}{9}\times9+\frac{h-1}{3}\times9=\frac{1}{3}\times9$ $2+h+3\times(h-1)=3$ Use the distributive property to simplify the left side. $2+h+3h-3=3$ Group like terms on the left side. $4h-1=3$ Add 1 to both sides. $4h=4$ Divide both sides by 4. $h=1$
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