Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 2 - Section 2.1 - Linear Equations in One Variable - Exercise Set: 27

Answer

$n=1$

Work Step by Step

We are given that $\frac{n-3}{4}+\frac{n+5}{7}=\frac{5}{14}$. First, we can multiply each term by 28. Since this is the least common denominator of each term, this will eliminate all fractions from the equation. $\frac{n-3}{4}\times28+\frac{n+5}{7}\times28=\frac{5}{14}\times28$ $7\times(n-3)+4\times(n+5)=10$ Use the distributive property to simplify the left side. $7n-21+4n+20=10$ Group like terms on the left side. $11n-1=10$ Add 1 to both sides. $11n=11$ Divide both sides by 11. $n=1$
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