## Intermediate Algebra (6th Edition)

$r=10$
We are given that $\frac{4r}{5}-\frac{r}{10}=7$. First, we can multiply each term by 10. Since this is the least common denominator of each term, this will eliminate all fractions from the equation. $\frac{4r}{5}\times10-\frac{r}{10}\times10=7\times10$ $8r-r=70$ Group like terms on the left side. $7r=70$ Divide both sides by 7. $r=10$