Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 2 - Review - Page 113: 84

Answer

no solution

Work Step by Step

Using the properties of equality, the given expression, $ \left| \dfrac{4(x-1)}{7} \right|+10\lt2 ,$ is equivalent to \begin{array}{l}\require{cancel} \left| \dfrac{4(x-1)}{7} \right|\lt2-10 \\\\ \left| \dfrac{4(x-1)}{7} \right|\lt-8 .\end{array} The left side of the expression, $ \left| \dfrac{4(x-1)}{7} \right|\lt-8 ,$ always gives a non-negative value. This will never be less than or equal to the negative value at the right. Hence, there is no solution.
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