Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 2 - Review - Page 112: 64

Answer

$ 260 \le T(c) \le 538 $

Work Step by Step

We know the formula: $T(F) = (1.8 \times T(c)) +32$ We have the inequality: $ 500 \lt T(F) \lt 1000$ We substitute: $ 500 \lt T(F) = (1.8 \times T(c)) +32 \lt 1000$ Now, follow PEMDAS. In other words, first address parentheses, and then resolve exponents. Next, simplify division and multiplication, and lastly address subtraction and addition. This gives: $ 260 \le T(c) \le 538 $
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