Intermediate Algebra (6th Edition)

Original Equation $\frac{2(t+1)}{3}$=$\frac{2(t-1)}{3}$ Multiply both sides by 3 2(t+1)=2(t-1) Distribute 2t+2=2t-2 Subtract 2t from both sides 2=-2 The sides of the equation are not equal, so there is no solution