Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 2 - Cumulative Review: 43

Answer

$x=-20$ and $x=24$

Work Step by Step

We are given that $|\frac{x}{2}-1|=11$. So, $\frac{x}{2}-1=11$ and $\frac{x}{2}-1=-11$. We can solve both of these equations for x. For $\frac{x}{2}-1=11$, add 1 to both sides of the equation. $\frac{x}{2}=12$ Multiply both sides of the equation by 2. $x=24$ For $\frac{x}{2}-1=-11$, add 1 to both sides of the equation. $\frac{x}{2}=-10$ Multiply both sides of the equation by 2. $x=-20$
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