## Intermediate Algebra (6th Edition)

$x=-20$ and $x=24$
We are given that $|\frac{x}{2}-1|=11$. So, $\frac{x}{2}-1=11$ and $\frac{x}{2}-1=-11$. We can solve both of these equations for x. For $\frac{x}{2}-1=11$, add 1 to both sides of the equation. $\frac{x}{2}=12$ Multiply both sides of the equation by 2. $x=24$ For $\frac{x}{2}-1=-11$, add 1 to both sides of the equation. $\frac{x}{2}=-10$ Multiply both sides of the equation by 2. $x=-20$