## Intermediate Algebra (6th Edition)

$x= -5$ and $x=5$
We are given that $|x|=5$. The solution set will be all values of x that have an absolute value of 5 (or all values of x that are exactly 5 units away from 0 on the number line). -5 and 5 are both 5 units from 0 on the number line, so $x= -5$ and $x=5$. $|-5|=5$ and $|5|=5$