## Intermediate Algebra (6th Edition)

$p=-2$ and $p=2$
We are given that $|p|=2$. The solution set will be all values of p that have an absolute value of 2 (or all values of p that are exactly 2 units away from 0 on the number line). -2 and 2 are both 2 units from 0 on the number line, so $p= -2$ and $p=2$. $|-2|=2$ and $|2|=2$