Intermediate Algebra (6th Edition)

$(-1,0)$
We are given that $-2x-5\lt-3$ and $6x\lt0$. Therefore, any solution must satisfy both inequalities. We can first solve $-2x-5\lt-3$. Add 5 to both sides. $-2x\lt2$ Divide both sides by -2 (which will reverse the inequality sign). $x\gt-1$ Next, we can solve $6x\lt0$. Divide both sides by 6. $x\lt0$ The solution set consists of all values of x that are greater than -1 and less than 0.