Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 2 - Cumulative Review - Page 115: 40

Answer

$(-1,0)$

Work Step by Step

We are given that $-2x-5\lt-3$ and $6x\lt0$. Therefore, any solution must satisfy both inequalities. We can first solve $-2x-5\lt-3$. Add 5 to both sides. $-2x\lt2$ Divide both sides by -2 (which will reverse the inequality sign). $x\gt-1$ Next, we can solve $6x\lt0$. Divide both sides by 6. $x\lt0$ The solution set consists of all values of x that are greater than -1 and less than 0.
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