## Intermediate Algebra (6th Edition)

$(-∞,3)$
We are given that $x+3\leq1$ or $3x-1\lt8$. Therefore, a solution for x will only need to satisfy at least one of the inequalities. First, we can solve $x+3\leq1$ Subtract 3 from both sides. $x\leq-2$ Next, we can solve $3x-1\lt8$ Add 1 to both sides. $3x\lt9$ Divide both sides by 3. $x\lt3$ Any number that is less than or equal to -2 will also be less than 3. Therefore, the solution set is any number that is less than 3.