## Intermediate Algebra (6th Edition)

$x\geq2.5$
We are given that $-(x-3)+2\leq3(2x-5)+x$ We can simplify both sides by using the distributive property. $3-x+2\leq6x-15+x$ Now we combine like terms. $5-x\leq7x-15$ Add 15 to both sides. $20-x\leq7x$ Add x to both sides. $20\leq8x$ Divide both sides by 8. $x\geq\frac{20}{8}$