## Intermediate Algebra (6th Edition)

We assume that the first number is x. The second number is 2 more than three times the first number, or 2+3x. Also, the difference of the two numbers is 24. So $2+3x-x=24$ We can solve this equation to find x. $2+2x=24$ $2x=22$ $x=11$ Plugging this into the value of the second number, we get: $2+3\times11=35$ So the numbers are 11 and 35