## Intermediate Algebra (6th Edition)

We are give that the second number is 3 more than twice the first number. So, we assume the first number is x. The second number is three more than two times x, or 3+2x. The third number is four times the first number, or 4x. $x+(3+2x)+4x=164$ $7x+3=164$ $7x=161$ $x=23$ So the numbers are: $23$ $3+2\times23=49$ $4\times23=92$