## Intermediate Algebra (6th Edition)

$3x+3$
An integer has a value of exactly 1 less than its next consecutive integer. And each following consecutive integer will be exactly 1 more in value than the previous integer. $x+(x+1)+(x+1+1)=(x+x+x)+(1+1+1)=3x+3$ Answer check: x=2 $2+3+4=3x+3=3\times2+3=9$