Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 2 - Cumulative Review - Page 115: 12b

Answer

$\frac{-12}{-4}=3$

Work Step by Step

$\frac{-12}{-4}$ can be reduced to 3. Since, both the numerator and the denominator are both negative, the resulting quotient of 3 will be positive. Therefore, $\frac{-12}{-4}=3$, so $\frac{-12}{-4}$ and 3 are equal to each other.
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