## Intermediate Algebra (6th Edition)

The absolute value of x, written by the form $|x|$, is the distance between x and 0 on the number line. It is equal to: x if $x\geq0$ -x if $x\lt0$ Since $-8\lt0$, $|-8|=8$ Since an additional negative sign is outside of the absolute value sign, this problem asks us to find the opposite of the absolute value of -8. $|-8|=8, so -|-8|=-8$