Answer
$20$
Work Step by Step
Cancelling the common factors between the numerator and the denominator, the given expression, $
\dfrac{5\cdot4\cdot3\cdot2\cdot1}{3\cdot2\cdot1}
,$ simplifies to
\begin{array}{l}\require{cancel}
\dfrac{5\cdot4\cdot\cancel{3\cdot2\cdot1}}{\cancel{3\cdot2\cdot1}}
\\\\=
5\cdot4
\\\\=
20
.\end{array}