Answer
$S_{12}=-696$
Work Step by Step
Using $S_{n}=\dfrac{n}{2}(2a_1+(n-1)d)$, the sum of the first $
12
$ terms of the sequence $
-3,-13,-23,...,-113
$ is
\begin{array}{l}
S_{12}=\dfrac{12}{2}(2(-3)+(12-1)(-10))\\\\
S_{12}=6(-6-110)\\\\
S_{12}=6(-116)\\\\
S_{12}=-696
.\end{array}