Answer
$S_{∞}=67.5$
Work Step by Step
Given geometric sequence
$45,15,5,...$
$a_{1}= 45$
Common ratio $r = \frac{a_{n}}{a_{n-1}}$
$r= \frac{a_{2}}{a_{1}} = \frac{15}{45} = \frac{1}{3}$
$|r| \lt 1$, So $S_{∞}$ exists.
Sum of the terms of an infinite geometric sequence is
$S_{∞}=\frac{a_{1}}{1-r}$
Substituting $a_{1}$ and $r$
$S_{∞}=\frac{45}{1-\frac{1}{3}}$
$S_{∞}=\frac{45}{\frac{2}{3}}$
$S_{∞}=45 \times \frac{3}{2}$
$S_{∞}= \frac{135}{2}$
$S_{∞}=67.5$