Answer
$S_{8}=-36$
Work Step by Step
Using $S_n=\dfrac{n}{2}(2a_1+(n-1)d)$, the sum of $
-1,-2,-3,...,-8
$ is
\begin{array}{l}
S_{8}=\dfrac{8}{2}(2\cdot(-1)+(8-1)(-1))\\\\
S_{8}=4(-2+-7)\\\\
S_{8}=4(-9)\\\\
S_{8}=-36
.\end{array}
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