Answer
$S_6=36$
Work Step by Step
Using $S_n=\dfrac{n}{2}(2a_1+(n-1)d)$, the sum of the first $
6$
terms of the sequence $
1,3,5,7,...
$ is
\begin{array}{l}
S_6=\dfrac{6}{2}(2\cdot1+(6-1)2)\\\\
S_6=3(2+10)\\\\
S_6=36
.\end{array}
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