Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 11 - Section 11.1 - Sequences - Vocabulary, Readiness & Video Check - Page 638: 5

Answer

$a_1=-1$

Work Step by Step

Substituting $n=1$ into the equation $ a_n=\dfrac{(-1)^n}{n} $ results to \begin{array}{l} a_1=\dfrac{(-1)^1}{1} \\\\ a_1=-1 .\end{array}
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