Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 11 - Cumulative Review - Page 669: 1c

Answer

$\dfrac{-1}{8}$

Work Step by Step

Using rules on integer operations, the expression $ \dfrac{-3}{8}\div3 $ simplifies to \begin{array}{l}\require{cancel} \dfrac{-3}{8}\cdot\dfrac{1}{3} \\\\= \dfrac{-\cancel{3}}{8}\cdot\dfrac{1}{\cancel{3}} \\\\= \dfrac{-1}{8} .\end{array}
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.