Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 10 - Section 10.1 - The Parabola and the Circle - Exercise Set - Page 610: 86

Answer

$$\frac{\sqrt{10}}{4}$$

Work Step by Step

$$\frac{\sqrt5}{\sqrt8}$$ $$\frac{\sqrt5}{\sqrt8}\times \frac{\sqrt8}{\sqrt8}$$ $$\frac{\sqrt{40}}{8}$$ $$\frac{2\sqrt{10}}{8}$$ $$\frac{\sqrt{10}}{4}$$
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