Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 10 - Section 10.1 - The Parabola and the Circle - Exercise Set - Page 610: 26

Answer

See graph

Work Step by Step

$$(x-3)^2+y^2=9$$ The center is (3,0) and the radius is $\sqrt9=3$. Points to plot are: $$(6,0)$$ $$(0,0)$$ $$(3,3)$$ $$(3.-3)$$ Plot these points and connect with a circle.
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