## Intermediate Algebra (6th Edition)

$\frac{6(7-9)^{3}+(-2)}{(-2)(-5)(-5)}$ =$\frac{6(-2)^{3}+(-2)}{10(-5)}$ =$\frac{6(-8)+(-2)}{-50}$ =$\frac{-50}{-50}$ = 1