Intermediate Algebra (6th Edition)

$8-6[\sqrt[3] 8(-2)+\sqrt 4(-5)]=8-6[(\sqrt[3] 8\times-2)+(\sqrt 4\times-5)]=8-6[(2\times-2)+(2\times-5)]$ To simplify the expression, first perform the operations within parentheses. $8-6[(2\times-2)+(2\times-5)]=8-6[(-4)+(-10)]$ Next, perform the operation in brackets. $8-6[-(4+10)]=8-6[-14]$ Finally, perform the remaining operations. $8-(6\times-14)=8-(-84)=8+84=92$ Notes: We know that $\sqrt[3] 8=2$, because $2^{3}=2\times2\times2=8$ and that $\sqrt 4=2$, because $2^{2}=2\times2=4$