Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 1 - Sections 1.2-1.3 - Integrated Review - Algebraic Expressions and Operations on Whole Numbers: 11

Answer

35

Work Step by Step

$9+2[(8-10)^{2}+(-3)^{2}]=9+2\times[(8-10)^{2}+(-3)^{2}]$ To evaluate the expression, we must first evaluate the terms within parentheses. $9+2\times[(-2)^{2}+(-3)^{2}]=9+2\times[(-2\times-2)+(-3\times-3)]=9+2\times[4+9]$ Next, we must perform the operation in brackets. $9+2\times[13]$ Finally, we perform the last operations. $9+26=35$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.