## Intermediate Algebra (6th Edition)

$9+2[(8-10)^{2}+(-3)^{2}]=9+2\times[(8-10)^{2}+(-3)^{2}]$ To evaluate the expression, we must first evaluate the terms within parentheses. $9+2\times[(-2)^{2}+(-3)^{2}]=9+2\times[(-2\times-2)+(-3\times-3)]=9+2\times[4+9]$ Next, we must perform the operation in brackets. $9+2\times[13]$ Finally, we perform the last operations. $9+26=35$