## Intermediate Algebra (6th Edition)

$\frac{11}{12}b-\frac{7}{6}$
We are given the expression $\frac{3}{4}b-\frac{1}{2}+\frac{1}{6}b-\frac{2}{3}$. We can simplify by grouping like terms and then finding a common denominator for each group of like terms. $(\frac{3}{4}b\times\frac{3}{3}+\frac{1}{6}b\times\frac{2}{2})-(\frac{1}{2}\times\frac{3}{3}+\frac{2}{3}\times\frac{2}{2})$ $=(\frac{9}{12}b+\frac{2}{12}b)-(\frac{3}{6}+\frac{4}{6})=\frac{11}{12}b-(\frac{7}{6})=\frac{11}{12}b-\frac{7}{6}$