Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 1 - Section 1.4 - Properties of Real Numbers and Algebraic Expressions - Exercise Set: 82

Answer

$y^{2}-11yz-11$

Work Step by Step

We are given the expression $-4(yz+3)-7yz+1+y^{2}$. We can use the distributive property and then group like terms to simplify. $-4(yz+3)-7yz+1+y^{2}=-4yz-12-7yz+1+y^{2}$ $=(y^{2})+(-(4yz+7yz))+(1+(-12))=y^{2}-11yz-11$
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