Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 1 - Section 1.4 - Properties of Real Numbers and Algebraic Expressions - Exercise Set: 52

Answer

$15a+5b+45c$

Work Step by Step

To find a product using the distributive property, you take the coefficent--in this case the 5 outside of the parentheses--and multiply it by each term within the parentheses separately. The first term within the parentheses is $3a$, so the first term of the product is $5\times3a$, or $15a$. The second term within the parentheses is $b$, so the second term of the product is $5\times b$, or $5b$. The third term within the parentheses is $9c$, so the third term of the product is $5\times 9c$, or $45c$. The terms within the parentheses are connected by plus signs, so the terms within the product will be too. The final product after distributing the 5, therefore, is $15a+5b+45c$.
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