## Intermediate Algebra (6th Edition)

Published by Pearson

# Chapter 1 - Section 1.3 - Operations on Real Numbers and Order of Operations - Exercise Set: 96a

#### Answer

When r=2: $A=3.14*4$ $A=12.56$ When r=3: $A=3.14*9$ $A=28.26$ When r=7: $A=3.14*49$ $A=153.86$ When r=10: $A=3.14*100$ $A=314$

#### Work Step by Step

The formula for Area is $3.14r^2$; simply substitute values for r to find that circle’s radius.

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