## Intermediate Algebra (6th Edition)

Published by Pearson

# Chapter 1 - Section 1.3 - Operations on Real Numbers and Order of Operations - Exercise Set: 90

#### Answer

$\frac{7}{18}$

#### Work Step by Step

We are asked to evaluate the expression $\frac{y}{2x}-\frac{\sqrt x}{3y}$, where $x=9$ and $y=-2$ $\frac{-2}{2\times9}-\frac{\sqrt 9}{3\times-2}=\frac{-2}{18}-\frac{3}{-6}=-\frac{2}{18}-(-\frac{3}{6})=-\frac{2}{18}+\frac{3}{6}$ $=-\frac{2}{18}+(\frac{3}{6}\times\frac{3}{3})=-\frac{2}{18}+\frac{9}{18}=\frac{7}{18}$ We know that $\sqrt 9=3$ because $3^{2}=3\times3=9$

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.