Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 1 - Section 1.3 - Operations on Real Numbers and Order of Operations - Exercise Set: 89



Work Step by Step

$\frac{\sqrt x}{y}-\frac{y}{x}$ where $x=9$ and $y=-2$. We can plug in this value to evaluate the expression. $\frac{\sqrt x}{y}-\frac{y}{x}=\frac{\sqrt 9}{-2}-\frac{-2}{9}=\frac{3}{-2}-(-\frac{2}{9})=(-\frac{3}{2}\times\frac{9}{9})+(\frac{2}{9}\times\frac{2}{2})=-\frac{27}{18}+\frac{4}{18}=-\frac{23}{18}$ We know that $\sqrt 9=3$ because $3^{2}=3\times3=9$
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