Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 1 - Section 1.3 - Operations on Real Numbers and Order of Operations - Exercise Set: 84

Answer

$$ \frac{2}{3}$$

Work Step by Step

We have $\frac{(-2)^4+3\sqrt {120-20}}{4^3+|5(-1)|}$ Solving $$\frac{16+3\sqrt {100}}{64+|-5|}$$ $$\frac{16+3*10}{64+5}$$ $$\frac{46}{69} = \frac{2}{3}$$
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