## Intermediate Algebra (6th Edition)

Published by Pearson

# Chapter 1 - Section 1.3 - Operations on Real Numbers and Order of Operations - Exercise Set: 73

-2.1

#### Work Step by Step

$\frac{(3-\sqrt 9)-(-5-1.3)}{-3}=\frac{(3-3)-(-(5+1.3))}{-3}=\frac{0-(-6.3)}{-3}=\frac{6.3}{-3}=-2.1$ We know that $\sqrt 9=3$, because $3^{2}=3\times3=9$

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