Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 1 - Section 1.3 - Operations on Real Numbers and Order of Operations - Exercise Set: 71

Answer

-11

Work Step by Step

$25-[(3-5)+(14-18)]^{2}$ To simplify this expression, first perform the operations in parentheses. $25-[-2+(-4)]^{2}=25-[-(2+4)]^{2}=25-[-6]^{2}$ Next, perform the exponent on the number in brackets. $25-(-6\times-6)=25-36$ Finally, perform the remaining operation. $25-36=25+(-36)=-11$
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