Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 1 - Section 1.3 - Operations on Real Numbers and Order of Operations - Exercise Set - Page 27: 68

Answer

-3

Work Step by Step

$\frac{(-1-2)(-3^{2})}{-6-3}=\frac{(-(1+2))\times(-(3^{2}))}{-(6+3)}=\frac{(-3)\times(-(9))}{-9}=\frac{(-3)\times(-9)}{-9}=\frac{27}{-9}=-\frac{27}{9}=-3$
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