## Intermediate Algebra (6th Edition)

Published by Pearson

# Chapter 1 - Section 1.3 - Operations on Real Numbers and Order of Operations - Exercise Set: 46

#### Answer

$-\frac{2}{5}$

#### Work Step by Step

$-\sqrt \frac{4}{25}=-(\sqrt \frac{4}{25})=-(\frac{2}{5})=-\frac{2}{5}$ because $-(\frac{2}{5}^{2})=-(\frac{2}{5}\times\frac{2}{5})=-(\frac{4}{25})=-\frac{4}{25}$ Due to order of operations, we must first evaluate the square root and then consider the negative sign.

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