Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 1 - Section 1.3 - Operations on Real Numbers and Order of Operations - Exercise Set: 41

Answer

$-\frac{1}{27}$

Work Step by Step

$(-\frac{1}{3})^{3}=-\frac{1}{3}\times-\frac{1}{3}\times-\frac{1}{3}=(-\frac{1}{3}\times-\frac{1}{3})\times-\frac{1}{3}=\frac{1}{9}\times-\frac{1}{3}=-\frac{1}{27}$
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