Intermediate Algebra (6th Edition)

$\frac{2}{3}$ $\ne$ $2(n+\frac{1}{4})$
From the problem: "Two-thirds:" $\frac{2}{3}$ "is not equal to:" $\ne$ "twice the sum of:" $2(addition)$ "the sum of $n$ and one-fourth": $(n+\frac{1}{4})$ Combine: $\frac{2}{3}$ $\ne$ $2(n+\frac{1}{4})$