Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 1 - Review - Page 44: 68

Answer

$\frac{7}{3}$

Work Step by Step

$\frac{(2+4)^2+(-1)^5}{12\div2\times3-3}$ $\frac{36-1}{6\times3-3}$ $\frac{35}{18-3}$ $\frac{35}{15}$ $\frac{7}{3}$
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