Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 1 - Review: 49

Answer

$-\frac{2}{15}$

Work Step by Step

$(-\frac{4}{5})-(-\frac{2}{3})=-\frac{4}{5}+\frac{2}{3}=\frac{2}{3}+(-\frac{4}{5})$ $=(\frac{2}{3}\times\frac{5}{5})+(-\frac{4}{5}\times\frac{3}{3})=\frac{10}{15}+(-\frac{12}{15})=-\frac{2}{15}$
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