## Intermediate Algebra (6th Edition)

Volume of the sphere is exactly $36π$ mi.$^{3}$ or approximately $113\frac{1}{7}$ mi.$^{3}$ Surface area of the sphere is exactly $36π$ mi.$^{2}$ or approximately $113\frac{1}{7}$ mi.$^{2}$
Let r = $3$ mi. $V$ = $\frac{4}{3}$π$r^{3}$ $V$ = $\frac{4}{3}$ π$($3$mi.)^{3}$ $V$ = $\frac{4}{3}$ π$($27$mi.)^{3}$ $V$ = $36π$ mi.$^{3}$ $V$ = $36$ times$\frac{22}{7}$ mi.$^{3}$ $V$ = $\frac{792}{7}$ or $113\frac{1}{7}$ mi.$^{3}$ Volume of the sphere is exactly $36π$ mi.$^{3}$ or approximately $113\frac{1}{7}$ mi.$^{3}$ $SA$ = ${4}$ π $r^{2}$ $SA$ = ${4}$ π $(3$mi.)$^{2}$ $SA$ = ${4}$ π ($9$ mi.)$^{2}$ $SA$ = $36π$ mi.$^{2}$ $SA$ = ${36}$ times $\frac{22}{7}$ mi.$^{2}$ $SA$ = $\frac{792}{7}$ or $113\frac{1}{7}$ mi.$^{2}$ Surface area of the sphere is exactly $36π$ mi.$^{2}$ or approximately $113\frac{1}{7}$ mi.$^{2}$