Answer
Volume of the sphere is exactly $36π$ mi.$^{3}$ or approximately $113\frac{1}{7}$ mi.$^{3}$
Surface area of the sphere is exactly $36π$ mi.$^{2}$ or approximately $113\frac{1}{7}$ mi.$^{2}$
Work Step by Step
Let r = $3$ mi.
$V$ = $\frac{4}{3}$π$r^{3}$
$V$ = $\frac{4}{3}$ π$($3$ mi.)^{3}$
$V$ = $\frac{4}{3}$ π$($27$ mi.)^{3}$
$V$ = $36π$ mi.$^{3}$
$V$ = $36$ times$\frac{22}{7}$ mi.$^{3}$
$V$ = $\frac{792}{7}$ or $113\frac{1}{7}$ mi.$^{3}$
Volume of the sphere is exactly $36π$ mi.$^{3}$ or approximately $113\frac{1}{7}$ mi.$^{3}$
$SA$ = ${4}$ π $r^{2}$
$SA$ = ${4}$ π $(3$mi.)$^{2}$
$SA$ = ${4}$ π ($9$ mi.)$^{2}$
$SA$ = $36π$ mi.$^{2}$
$SA$ = ${36}$ times $\frac{22}{7}$ mi.$^{2}$
$SA$ = $\frac{792}{7}$ or $113\frac{1}{7}$ mi.$^{2}$
Surface area of the sphere is exactly $36π$ mi.$^{2}$ or approximately $113\frac{1}{7}$ mi.$^{2}$
