Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Appendix A - A.3 - Exercise Set: 1

Answer

V = $72$ in.$^{3}$ SA = $108$ in.$^{2}$

Work Step by Step

Let $h$ = $3$ in., $l$ = $6$ in., and $w$ = $4$ in. $V = lwh$ $V$ = $3$ in. x $6$ in. x $4$ in. = $72$ in.$^{3}$ The volume of the rectangular box is $72$ in.$^{3}$ $SA$ = $2lh$ + $2wh$ + $2lw$ $SA$ = $2$($6$ in.)($3$ in.) + $2$($4$ in.)($3$ in.) + $2$($6$ in.)($4$ in.) $SA$ = $36$ in.$^{2}$ + $24$ in.$^{2}$ + $48$ in.$^{2}$ $SA$ = $108$ in.$^{2}$ The surface area of the rectangular box is $108$ in.$^{2}$
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